Transcribed image text 1. Write the equilibrium expression for the following reaction 2 points N2 g + 3H2 g 2NH3g 2. Calculate the equilibrium constant for the reaction below using the balanced chemical equation and the concentrations of the substances at equilibrium. 2 points N2g + 3H2g 2NH3 8 [N2] - M [H2] = M NH3 - M 3. Are reactants or products favored at equilibrium? 2 points 4. Calculate the equilibrium constant for the reaction below using the balanced chemical equation and the concentrations of the substances at equilibrium. 2 points N2 g + 3H2g 2NH3g [N2] M [H2] M NH3 - M 5. Compare your answers to Problems 2 & 4. Are your solutions to Problem 2 & 4 in agreement? 1 point Make a statement regarding the equilibrium constants you determined and the concentrations of substances at equilibrium. 1 point 5. Compare your answers to Problems 2 & 4. Are your solutions to Problem 2 & 4 in agreement? 1 point Make a statement regarding the equilibrium constants you determined and the concentrations of substances at equilibrium. 1 point Previous question Next question
Answer The numbers 2 and 3 appearing before the H2 and NH3 terms respectively in the equation are known as the coefficients of the particular reactants/products. They represent the relative number of molecules or moles of individual reactants/products. The equation as given in the question is b
SolveStudyTextbooksGuidesUse appLogin>>Class 12>>Chemistry>>Chemical Kinetics>>Factors Influencing Rate of a Reaction>>For the reaction 2NH3 g → N2g + 3Question EasyOpen in AppUpdated on 2022-09-05SolutionVerified by TopprSince Rate is independent of Concentration Of Reactant. Order of this Reaction is as Two molecules of react to form Products, Molecularity of this reaction is Solve any question of Chemical Kinetics with-Patterns of problems > Was this answer helpful? 00Similar questionsFor a reaction Rate = k I Write the order and molecularity of this reaction. II Write the unit of .Delhi 2016EasyView solution > For a reaction i Write the order and molecularity of this reaction. ii Write the unit of .MediumView solution > What is the difference between the order and molecularity of a reaction? solution > Write the difference between order and molecularity of a solution > Distinguish between order and molecularity of a reaction. MediumView solution > More From ChapterChemical KineticsView chapter > Revise with ConceptsRate Law, Rate Expression and Rate ConstantExampleDefinitionsFormulaes >Order and Molecularity of a >Learn with VideosUnderstand Rate Law with example12 minsIntroduction, Characteristics and Applications of Rate Constant5 minsUnderstand Order of Reactions5 minsSolve questions on the Order of Reaction13 minsUnderstand Elementary and Complex Reactions6 minsUnits of Rate Constant for Reactions of different orders4 minsMolecularity and compare it with order of reaction18 minsExamples of finding molecularity of reactions3 minsUnderstand slowest step as rate determining step9 mins Practice more questions Easy Questions 32 Qs >Medium Questions 510 Qs >Hard Questions 453 Qs > Shortcuts & Tips Common Misconceptions > Mindmap > Important Diagrams > Cheatsheets >
Enla reacción química N2 + 3H2 → 2NH3, la velocidad de reacción del hidrógeno es de 0,084 M/s. Como la reacción es una reacción redox, la velocidad de reacción del amoniaco es la mitad de la velocidad de reacción del hidrógeno, que es de 0,042 M/s. La velocidad de reacción del nitrógeno es también de 0,042 M/s. N2(g) + 3H2(g) →
You first need to solve for the moles of N2. This is done by dividing the mass given by the molar mass of N2. The molar mass is calculated by adding the molar mass of all the atoms N * 2 = N2Using as the molar mass of N2 perform the following / = N2Because the equation in balanced we already know that there are two moles of ammonia produced for every one mole of N2. This means we just need to multiply the number of moles of N2 by 2 in order to get the number of moles of ammonia N2 * 2mol NH3/1mol N2 = NH3After solving for the moles of ammonia, we need to convert the moles to grams. This is done using the molar mass of ammonia which is solved as N2 + 3 H = NH3The moles of ammonia we found earlier is then multiplied by the molar mass of ammonia to convert it to NH3 * NH3 = NH3Therefore, your answer should be of ammonia are produced.
N2g) + 3H2(g) -----> 2NH3(g) ; ∆rH° = -92.4 KJ/mol enthalpy of formation of NH3 means heat released in the formation of 1 mole of NH3 . so, divide both sides by 2 in above reaction 1/2N2(g) + 3/2H2(g) ---> NH3(g) ; Therefore , ∆fH° = ∆rH°/2 = -92.4/2 = 46.2 KJ/mol . Advertisement Advertisement dharamrajktr6 dharamrajktr6 Answer:
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n2 g 3h2 g 2nh3 g